54 lines
1.3 KiB
Bash
Executable File
54 lines
1.3 KiB
Bash
Executable File
#!/bin/bash
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prog=unload-zfs.sh
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. ../.script-config
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spl_module=${SPLBUILD}/modules/spl/spl.ko
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zlib_module=/lib/modules/${KERNELSRCVER}/kernel/lib/zlib_deflate/zlib_deflate.ko
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zavl_module=${ZFSBUILD}/lib/libavl/zavl.ko
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znvpair_module=${ZFSBUILD}/lib/libnvpair/znvpair.ko
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zcommon_module=${ZFSBUILD}/lib/libzcommon/zcommon.ko
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zpool_module=${ZFSBUILD}/lib/libzpool/zpool.ko
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zctl_module=${ZFSBUILD}/lib/libdmu-ctl/zctl.ko
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zpios_module=${ZFSBUILD}/lib/libzpios/zpios.ko
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die() {
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echo "${prog}: $1" >&2
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exit 1
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}
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unload_module() {
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echo "Unloading $1"
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/sbin/rmmod $1 || die "Failed to unload $1"
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}
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if [ $(id -u) != 0 ]; then
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die "Must run as root"
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fi
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unload_module ${zpios_module}
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unload_module ${zctl_module}
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unload_module ${zpool_module}
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unload_module ${zcommon_module}
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unload_module ${znvpair_module}
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unload_module ${zavl_module}
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unload_module ${zlib_module}
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# Set DUMP=1 to generate debug logs on unload
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if [ -n "${DUMP}" ]; then
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sysctl -w kernel.spl.debug.dump=1
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# This is racy, I don't like it, but for a helper script it will do.
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SPL_LOG=`dmesg | tail -n 1 | cut -f5 -d' '`
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${SPLBUILD}/cmd/spl ${SPL_LOG} >${SPL_LOG}.log
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echo
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echo "Dumped debug log: ${SPL_LOG}.log"
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tail -n1 ${SPL_LOG}.log
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echo
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fi
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unload_module ${spl_module}
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echo "Successfully unloaded ZFS module stack"
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exit 0
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