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dmu_buf_will_clone: only check that current txg is clean 

dbuf_undirty() will (correctly) only removed dirty records for the given
(open) txg. If there is a dirty record for an earlier closed txg that
has not been synced out yet, then db_dirty_records will still have
entries on it, tripping the assertion.

Instead, change the assertion to only consider the current txg. To some
extent this is redundant, as its really just saying "did dbuf_undirty()
work?", but it it doesn't hurt and accurately expresses our
expectations.

Reviewed-by: Brian Behlendorf <behlendorf1@llnl.gov>
Reviewed-by: Kay Pedersen <mail@mkwg.de>
Signed-off-by: Rob Norris <rob.norris@klarasystems.com>
Original-patch-by: Kay Pedersen <mail@mkwg.de>
Sponsored-By: OpenDrives Inc.
Sponsored-By: Klara Inc.
Closes #15050
This commit is contained in:
Rob Norris 2023-07-24 17:54:05 +10:00 committed by Brian Behlendorf
parent 87a6e135c5
commit d4edecd1a2
1 changed files with 1 additions and 1 deletions
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2
module/zfs/dbuf.c
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@ -2701,7 +2701,7 @@ dmu_buf_will_clone(dmu_buf_t *db_fake, dmu_tx_t *tx)
*/
mutex_enter(&db->db_mtx);
VERIFY(!dbuf_undirty(db, tx));
ASSERT(list_head(&db->db_dirty_records) == NULL);
ASSERT0(dbuf_find_dirty_eq(db, tx->tx_txg));
if (db->db_buf != NULL) {
arc_buf_destroy(db->db_buf, db);
db->db_buf = NULL;