FreeBSD: Fix integer conversion for vnlru_free{,_vfsops}()
When reviewing #13875, I noticed that our FreeBSD code has an issue where it converts from `int64_t` to `int` when calling `vnlru_free{,_vfsops}()`. The result is that if the int64_t is `1 << 36`, the int will be 0, since the low bits are 0. Even when some low bits are set, a value such as `((1 << 36) + 1)` would truncate to 1, which is wrong. There is protection against this on 32-bit platforms, but on 64-bit platforms, there is no check to protect us, so we add a check. Reviewed-by: Alexander Motin <mav@FreeBSD.org> Reviewed-by: Ryan Moeller <ryan@iXsystems.com> Signed-off-by: Richard Yao <richard.yao@alumni.stonybrook.edu> Closes #13882
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@ -161,6 +161,12 @@ arc_prune_task(void *arg)
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int64_t nr_scan = (intptr_t)arg;
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int64_t nr_scan = (intptr_t)arg;
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arc_reduce_target_size(ptob(nr_scan));
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arc_reduce_target_size(ptob(nr_scan));
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#ifndef __ILP32__
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if (nr_scan > INT_MAX)
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nr_scan = INT_MAX;
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#endif
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#if __FreeBSD_version >= 1300139
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#if __FreeBSD_version >= 1300139
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sx_xlock(&arc_vnlru_lock);
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sx_xlock(&arc_vnlru_lock);
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vnlru_free_vfsops(nr_scan, &zfs_vfsops, arc_vnlru_marker);
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vnlru_free_vfsops(nr_scan, &zfs_vfsops, arc_vnlru_marker);
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